1. What is Double.longBitsToDouble()?

The Double.longBitsToDouble() method in Java converts the specified bit pattern (64-bit long) to a double-precision floating-point value following the IEEE 754 floating-point "double format" bit layout.

2. How Does the Calculator Work?

The calculator simulates Java's conversion method:

Where:

• \( binary \) — 64-bit long integer representing the bits of a double
• \( decimal \) — Resulting double-precision floating-point number

Explanation: The method interprets the 64-bit long value as if it were a double according to IEEE 754 floating-point format.

3. IEEE 754 Floating-Point Representation

Details: IEEE 754 double-precision format uses 1 sign bit, 11 exponent bits, and 52 fraction bits. This calculator helps visualize how bit patterns translate to decimal numbers.

4. Using the Calculator

Tips: Enter the 64-bit long integer value representing the binary pattern of a double. The calculator will convert it to its decimal equivalent.

5. Frequently Asked Questions (FAQ)

Q1: What's the difference between this and Double.parseDouble()?
A: parseDouble() converts a string representation of a number, while longBitsToDouble() interprets raw bits as a double.

Q2: What's the reverse operation?
A: Double.doubleToLongBits() converts a double to its bit representation as a long.

Q3: What range of values can be represented?
A: Approximately ±5.0×10⁻³²⁴ to ±1.7×10³⁰⁸ with 15-17 significant decimal digits precision.

Q4: How are special values handled?
A: Special bit patterns represent NaN, infinity, and zero values according to IEEE 754.

Q5: Why would I need this conversion?
A: Useful for low-level numeric processing, binary data analysis, or understanding floating-point representation.