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03 Engines and Motion

DC Motor Efficiency Calculator: Formula and Inputs

Card No. 03·0619 · Updated · Standard formula, shown below

Motor efficiency 78.54 %
Electrical input power
24.00 W
Result
Mechanical output power
18.85 W
Result
Input voltage
12 V
You entered
You enter
Input voltage, Input current, Output torque, Rotational speed
You get
Motor efficiency, Electrical input power, Mechanical output power
Rounding
2 dp

A DC motor efficiency calculator is based on the ratio of useful mechanical output power to electrical input power. Enter the motor’s input voltage and current, plus its output torque and rotational speed, to estimate efficiency as a percentage.

Formula

The calculator uses efficiency = mechanical output power ÷ electrical input power × 100. For a rotating shaft, mechanical power is torque multiplied by angular speed. Since speed is entered in revolutions per minute, the conversion is:

Efficiency (%) = 100 × [torque (N·m) × 2π × speed (rpm) ÷ 60] ÷ [voltage (V) × current (A)]

  • Voltage, V: electrical input voltage in volts.
  • Current, I: electrical input current in amperes.
  • Torque, T: shaft output torque in newton-metres.
  • Speed, n: shaft rotational speed in revolutions per minute.
  • Input power, Pin: voltage multiplied by current, in watts, for the assumed DC electrical input.
  • Output power, Pout: torque multiplied by angular speed, in watts.
  • Efficiency: the output-to-input power ratio expressed as a percentage.

The formula assumes voltage and current describe the motor’s electrical input at the same operating condition, and torque and speed describe its shaft output at that same condition. If either power is measured at a different point in the drive system, the result will not represent the motor alone.

Worked Example

Using the calculator’s defaults—12 V, 2 A, 0.15 N·m and 1,200 rpm—first calculate electrical input power:

Pin = 12 V × 2 A = 24 W.

Then calculate mechanical output power. Convert revolutions per minute to angular speed in radians per second by multiplying by 2π and dividing by 60:

Pout = 0.15 N·m × 2π × 1,200 rpm ÷ 60 = 18.85 W (rounded to two decimal places).

Finally, divide output by input and multiply by 100:

Efficiency = 100 × 18.8496 W ÷ 24 W = 78.54%.

The estimated efficiency is therefore 78.54%, with 24.00 W of electrical input and 18.85 W of mechanical output. The difference, about 5.15 W, represents power not delivered as measured shaft output under these assumptions.

What the Calculator Measures

Efficiency describes how much input power becomes useful output power at a particular operating point. It is not a fixed property that a motor maintains at every speed or load. A motor can have different efficiency at startup, under light load, near its rated load, and at different supply voltages. For a meaningful comparison, make measurements under the same conditions and use steady-state readings where possible.

The calculator focuses on shaft efficiency: electrical power entering the motor compared with mechanical power leaving its shaft. It does not automatically include losses in a power supply, controller, gearbox, belt, or other transmission. If you want efficiency for a complete system, measure power at the system’s electrical boundary and useful output at its final mechanical boundary.

How to Get Useful Inputs

Use measurements rather than relying only on a motor’s nominal or maximum ratings. Voltage and current should be measured while the motor is operating at the chosen load. Torque and speed must be measured together at the shaft. A motor’s stall torque, for example, occurs at zero speed, so mechanical output power at stall is zero even though the current may be high.

Common measurement approaches include a torque sensor or dynamometer for shaft torque, and a tachometer or encoder for speed. Electrical readings may require instruments suited to the motor’s supply and controller. With pulse-width-modulated drive, current and voltage can vary quickly; a simple display reading may not capture the relevant average or waveform. Follow instrument instructions and use measurements appropriate to the circuit.

Convert units before entering values. This calculator expects volts, amperes, newton-metres and revolutions per minute. One N·m is approximately 8.8507 pound-inches, or 0.7376 pound-feet. One horsepower is approximately 745.7 watts. If torque is given in pound-feet, convert it to N·m by multiplying by about 1.3558; do not enter the pound-foot number as if it were N·m.

Interpreting Results and Common Errors

An efficiency between 0% and 100% is generally expected when all inputs are measured consistently and the boundaries are defined correctly. A calculated value above 100% is not evidence of an unusually efficient motor: it usually points to measurement error, mismatched units, readings taken at different times, or an incorrect system boundary. Check torque units especially carefully, and verify whether a current reading is in amperes or milliamperes.

  • Using rated values as simultaneous measurements: nameplate values may describe different conditions, not one operating point.
  • Mixing peak and average readings: electrical and mechanical measurements should represent the same interval and load.
  • Ignoring controller losses: power measured before a controller includes losses outside the motor; power measured at its output does not.
  • Rounding too early: keep extra digits in intermediate calculations, then round the final displayed result.
  • Assuming zero current or zero speed gives a normal efficiency figure: with zero input power the ratio is undefined, and with zero shaft speed output power is zero.

The calculator rejects negative inputs, but zero voltage, current, or speed can still make the efficiency calculation undefined or uninformative. Treat such cases as no usable operating-point result rather than as a meaningful efficiency rating.

Limits and Related Efficiency Figures

For a DC supply, input power is often estimated as voltage times current. This is suitable when those values are representative of the electrical power entering the motor. If voltage and current fluctuate substantially, their separate average readings do not always produce the true average power: in general, average instantaneous voltage multiplied by current is needed. A suitable power analyzer can account for changing waveforms.

Some specifications quote motor efficiency at a stated voltage, speed and load; others may report a broader drive-system figure. Check the definition and test conditions before comparing published numbers. The calculator does not predict efficiency from motor size, winding resistance, or a model number; it estimates efficiency from measured input and output power.

Efficiency also differs from power factor. Power factor is relevant to AC systems and describes a relationship between real and apparent electrical power; it is not an extra correction to apply to this DC formula. For a battery-powered motor driven by an electronic controller, however, choose the measurement boundary carefully: battery-side power includes controller losses, while motor-terminal power does not.

Frequently Asked Questions

What is the formula for DC motor efficiency?
Divide mechanical shaft output power by electrical input power and multiply by 100. For a rotating shaft, output power in watts is torque in N·m multiplied by 2π and speed in rpm, then divided by 60.

Can DC motor efficiency be more than 100%?
Not for a correctly measured motor operating as a power converter under the stated boundaries. A result above 100% usually indicates inconsistent readings, a unit conversion mistake, or a mismatch in what was included as input and output.

Can I calculate efficiency from voltage and current alone?
No. Those values estimate electrical input power, but efficiency also requires useful output power. For a rotating motor, that means measuring both shaft torque and speed, or obtaining equivalent reliable output-power data.

Why does efficiency change with motor load?
Motor losses do not stay in the same proportion to useful output as load changes. Electrical resistance, magnetic effects, friction, windage and controller losses all influence the operating-point result, so efficiency varies with load and speed.

Should I include the motor controller in the calculation?
Include it only if you intend to report efficiency for the motor-and-controller system. Measure electrical input before the controller for system input, and compare it with mechanical output at the shaft. For motor-only efficiency, measure electrical power at the motor terminals.

Related

Formula used
in v | Input voltage | V | 12 | 0 | 100000
in i | Input current | A | 2 | 0 | 100000
in t | Output torque | N·m | 0.15 | 0 | 100000
in n | Rotational speed | rpm | 1200 | 0 | 1000000
out eff | Motor efficiency | % | 100 * (t * 2 * pi * n / 60) / (v * i) | 2
out pin | Electrical input power | W | v * i | 2
out pout | Mechanical output power | W | t * 2 * pi * n / 60 | 2

Each line is one input (in, sel, list) or one result (out: label, unit, formula, decimals). How the calculators work

Method: the standard formula for this calculation, rounded as each result states. See how the calculators work or report an error.

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