This calculator finds the energy needed to heat water: enter the volume, the starting and target temperatures and the heater power. You get the energy in kilojoules, kilowatt-hours and BTU, and how long the heater needs if no heat is lost.
Formula
Heat Q = m × c × ΔT. For water, 1 litre has a mass of about 1 kg and the specific heat c is about 4.186 kJ/(kg·°C). ΔT = target − start. 1 kWh = 3,600 kJ and 1 BTU = 1.05506 kJ. Time = energy ÷ power.
- vol: litres of water (US gallons × 3.785)
- t1, t2: start and target temperature, °C
- kw: heater power, kW
Worked Example
50 L from 15 °C to 60 °C with a 3 kW heater.
- ΔT = 60 − 15 = 45 °C
- Q = 50 × 4.186 × 45 = 9,418.5 kJ
- 9,418.5 ÷ 3600 = 2.616 kWh; 9,418.5 ÷ 1.05506 = 8,927 BTU
- Time = 2.616 ÷ 3 = 0.872 h = 52.3 min
Limits and common mistakes
- If the target is below the start temperature the water is being cooled, not heated, and the calculator shows “Cannot compute”.
- Real heaters lose heat to the tank and pipes, so expect a longer time; divide by the heater efficiency if you know it.
- The formula is for liquid water. Melting ice or boiling water needs extra latent heat (334 kJ/kg to melt, 2,257 kJ/kg to boil).
- Fahrenheit: a 1 °F rise is 5/9 of a 1 °C rise.
Formula used
in vol | Water volume | L | 50 | 0 in t1 | Start temperature | °C | 15 | 0 | 100 in t2 | Target temperature | °C | 60 | 0 | 100 in kw | Heater power | kW | 3 | 0 out q | Energy needed | kJ | vol * 4.186 * (t2 - t1) + 0 * sqrt(t2 - t1) | 1 out kwh | Energy needed | kWh | q / 3600 | 3 out btu | Energy needed | BTU | q / 1.05505585262 | 0 out tmin | Heating time (no losses) | min | kwh / kw * 60 | 1
Each line is one input (in, sel, list) or one result (out: label, unit, formula, decimals). How the calculators work

Method: the standard formula for this calculation, rounded as each result states. See how the calculators work or report an error.
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